Base | Representation |
---|---|
bin | 1101111011010010000100… |
… | …1001110110100101011011 |
3 | 2000012211020121002221120002 |
4 | 3132310201021312211123 |
5 | 4001333202322004433 |
6 | 52322142141323215 |
7 | 3140156321650640 |
oct | 336644111664533 |
9 | 60184217087502 |
10 | 15312114641243 |
11 | 4973916590082 |
12 | 187371026650b |
13 | 870c06b81954 |
14 | 3ad178957dc7 |
15 | 1b848368b9e8 |
hex | ded2127695b |
15312114641243 has 32 divisors (see below), whose sum is σ = 17643036902400. Its totient is φ = 13017428434944.
The previous prime is 15312114641189. The next prime is 15312114641261. The reversal of 15312114641243 is 34214641121351.
It is a cyclic number.
It is not a de Polignac number, because 15312114641243 - 216 = 15312114575707 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 15312114641197 and 15312114641206.
It is not an unprimeable number, because it can be changed into a prime (15312114641443) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 2299458248 + ... + 2299464906.
It is an arithmetic number, because the mean of its divisors is an integer number (551344903200).
Almost surely, 215312114641243 is an apocalyptic number.
15312114641243 is a deficient number, since it is larger than the sum of its proper divisors (2330922261157).
15312114641243 is a wasteful number, since it uses less digits than its factorization.
15312114641243 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 10859.
The product of its digits is 69120, while the sum is 38.
Adding to 15312114641243 its reverse (34214641121351), we get a palindrome (49526755762594).
The spelling of 15312114641243 in words is "fifteen trillion, three hundred twelve billion, one hundred fourteen million, six hundred forty-one thousand, two hundred forty-three".
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