Base | Representation |
---|---|
bin | 100010110111010000110000… |
… | …010101010010100100010001 |
3 | 202002220022111000101102201002 |
4 | 202313100300111102210101 |
5 | 130044134140144322031 |
6 | 1302035204350551345 |
7 | 44203544446114340 |
oct | 4267206025224421 |
9 | 662808430342632 |
10 | 153331143354641 |
11 | 449464110a855a |
12 | 15244729808555 |
13 | 67730ac40cbc5 |
14 | 29c13a4685b57 |
15 | 12ad765507ccb |
hex | 8b7430552911 |
153331143354641 has 32 divisors (see below), whose sum is σ = 177628215582720. Its totient is φ = 129643243099200.
The previous prime is 153331143354629. The next prime is 153331143354643. The reversal of 153331143354641 is 146453341133351.
It is a cyclic number.
It is not a de Polignac number, because 153331143354641 - 238 = 153056265447697 is a prime.
It is not an unprimeable number, because it can be changed into a prime (153331143354643) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 368703896 + ... + 369119526.
It is an arithmetic number, because the mean of its divisors is an integer number (5550881736960).
Almost surely, 2153331143354641 is an apocalyptic number.
It is an amenable number.
153331143354641 is a deficient number, since it is larger than the sum of its proper divisors (24297072228079).
153331143354641 is a wasteful number, since it uses less digits than its factorization.
153331143354641 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 417845.
The product of its digits is 2332800, while the sum is 47.
Adding to 153331143354641 its reverse (146453341133351), we get a palindrome (299784484487992).
The spelling of 153331143354641 in words is "one hundred fifty-three trillion, three hundred thirty-one billion, one hundred forty-three million, three hundred fifty-four thousand, six hundred forty-one".
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