Base | Representation |
---|---|
bin | 1110111010110111111111… |
… | …0000100111111101010001 |
3 | 2011002021012102101011210021 |
4 | 3232231333300213331101 |
5 | 4122233132112301213 |
6 | 54520102515103441 |
7 | 3312123602343040 |
oct | 356557760477521 |
9 | 64067172334707 |
10 | 16404623556433 |
11 | 525518636a192 |
12 | 1a0b3ab2a1b81 |
13 | 91cc459a0a58 |
14 | 409db9190557 |
15 | 1d6ac666bd8d |
hex | eeb7fc27f51 |
16404623556433 has 16 divisors (see below), whose sum is σ = 18913480742016. Its totient is φ = 13937592366720.
The previous prime is 16404623556413. The next prime is 16404623556439. The reversal of 16404623556433 is 33465532640461.
It is a cyclic number.
It is not a de Polignac number, because 16404623556433 - 25 = 16404623556401 is a prime.
It is a super-2 number, since 2×164046235564332 (a number of 27 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (16404623556439) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 20061916 + ... + 20863597.
It is an arithmetic number, because the mean of its divisors is an integer number (1182092546376).
Almost surely, 216404623556433 is an apocalyptic number.
It is an amenable number.
16404623556433 is a deficient number, since it is larger than the sum of its proper divisors (2508857185583).
16404623556433 is a wasteful number, since it uses less digits than its factorization.
16404623556433 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 40926024.
The product of its (nonzero) digits is 18662400, while the sum is 52.
The spelling of 16404623556433 in words is "sixteen trillion, four hundred four billion, six hundred twenty-three million, five hundred fifty-six thousand, four hundred thirty-three".
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