Base | Representation |
---|---|
bin | 1111000010111100110101… |
… | …0100000101001001000001 |
3 | 2011120112022110100011222102 |
4 | 3300233031110011021001 |
5 | 4132021302043300423 |
6 | 55103525532520145 |
7 | 3325134654600056 |
oct | 360571524051101 |
9 | 64515273304872 |
10 | 16543363650113 |
11 | 52a9001550033 |
12 | 1a3226b020055 |
13 | 930056525141 |
14 | 4129bb33702d |
15 | 1da4e696cc28 |
hex | f0bcd505241 |
16543363650113 has 16 divisors (see below), whose sum is σ = 17034545493504. Its totient is φ = 16056373280640.
The previous prime is 16543363650101. The next prime is 16543363650119. The reversal of 16543363650113 is 31105636334561.
It is a cyclic number.
It is not a de Polignac number, because 16543363650113 - 240 = 15443852022337 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (16543363650119) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 87516806 + ... + 87705632.
It is an arithmetic number, because the mean of its divisors is an integer number (1064659093344).
Almost surely, 216543363650113 is an apocalyptic number.
It is an amenable number.
16543363650113 is a deficient number, since it is larger than the sum of its proper divisors (491181843391).
16543363650113 is a wasteful number, since it uses less digits than its factorization.
16543363650113 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 199912.
The product of its (nonzero) digits is 1749600, while the sum is 47.
Adding to 16543363650113 its reverse (31105636334561), we get a palindrome (47648999984674).
The spelling of 16543363650113 in words is "sixteen trillion, five hundred forty-three billion, three hundred sixty-three million, six hundred fifty thousand, one hundred thirteen".
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