Base | Representation |
---|---|
bin | 1111000011101001101100… |
… | …0111101110010110010001 |
3 | 2011121200101201222220122010 |
4 | 3300322123013232112101 |
5 | 4132220433022431423 |
6 | 55113240531533133 |
7 | 3326042255662014 |
oct | 360723307562621 |
9 | 64550351886563 |
10 | 16555406452113 |
11 | 5303121386461 |
12 | 1a3467015a1a9 |
13 | 9312254c4999 |
14 | 4134008d737b |
15 | 1da99dd45693 |
hex | f0e9b1ee591 |
16555406452113 has 16 divisors (see below), whose sum is σ = 22965352595456. Its totient is φ = 10596805747920.
The previous prime is 16555406452099. The next prime is 16555406452141. The reversal of 16555406452113 is 31125460455561.
It is not a de Polignac number, because 16555406452113 - 218 = 16555406189969 is a prime.
It is a super-3 number, since 3×165554064521133 (a number of 41 digits) contains 333 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (16555406412113) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 700835131 + ... + 700858752.
It is an arithmetic number, because the mean of its divisors is an integer number (1435334537216).
Almost surely, 216555406452113 is an apocalyptic number.
It is an amenable number.
16555406452113 is a deficient number, since it is larger than the sum of its proper divisors (6409946143343).
16555406452113 is a wasteful number, since it uses less digits than its factorization.
16555406452113 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1401694044.
The product of its (nonzero) digits is 2160000, while the sum is 48.
The spelling of 16555406452113 in words is "sixteen trillion, five hundred fifty-five billion, four hundred six million, four hundred fifty-two thousand, one hundred thirteen".
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