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1681530513131 = 7387776398111
BaseRepresentation
bin11000011110000011000…
…001110110011011101011
312221202022202022200021202
4120132003001312123223
5210022233302410011
63324252350354415
7232325615350040
oct30360301663353
95852282280252
101681530513131
11599151156757
12231a851bba0b
13c274c174811
145b55a82d1c7
152db1912823b
hex187830766eb

1681530513131 has 16 divisors (see below), whose sum is σ = 1922733496320. Its totient is φ = 1440573850080.

The previous prime is 1681530513121. The next prime is 1681530513133. The reversal of 1681530513131 is 1313150351861.

It is a cyclic number.

It is not a de Polignac number, because 1681530513131 - 210 = 1681530512107 is a prime.

It is a super-2 number, since 2×16815305131312 (a number of 25 digits) contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (1681530513133) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 207310766 + ... + 207318876.

It is an arithmetic number, because the mean of its divisors is an integer number (120170843520).

Almost surely, 21681530513131 is an apocalyptic number.

1681530513131 is a deficient number, since it is larger than the sum of its proper divisors (241202983189).

1681530513131 is an equidigital number, since it uses as much as digits as its factorization.

1681530513131 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 19634.

The product of its (nonzero) digits is 32400, while the sum is 38.

Adding to 1681530513131 its reverse (1313150351861), we get a palindrome (2994680864992).

The spelling of 1681530513131 in words is "one trillion, six hundred eighty-one billion, five hundred thirty million, five hundred thirteen thousand, one hundred thirty-one".

Divisors: 1 7 3877 7639 8111 27139 53473 56777 29616403 31446347 61959929 207314821 220124429 433719503 240218644733 1681530513131