Base | Representation |
---|---|
bin | 11101000110110010010… |
… | …011000011010100001011 |
3 | 21002012201222020010021110 |
4 | 131012302103003110023 |
5 | 230232302142201103 |
6 | 4130505020141403 |
7 | 264335416046265 |
oct | 35066223032413 |
9 | 7065658203243 |
10 | 2000151131403 |
11 | 701294196077 |
12 | 283786697863 |
13 | 1167c896b239 |
14 | 6cb44990b35 |
15 | 370663d2403 |
hex | 1d1b24c350b |
2000151131403 has 16 divisors (see below), whose sum is σ = 2670414624000. Its totient is φ = 1331661714144.
The previous prime is 2000151131399. The next prime is 2000151131437. The reversal of 2000151131403 is 3041311510002.
It is not a de Polignac number, because 2000151131403 - 22 = 2000151131399 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 2000151131403.
It is not an unprimeable number, because it can be changed into a prime (2000151131603) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 9488848 + ... + 9697346.
It is an arithmetic number, because the mean of its divisors is an integer number (166900914000).
Almost surely, 22000151131403 is an apocalyptic number.
2000151131403 is a deficient number, since it is larger than the sum of its proper divisors (670263492597).
2000151131403 is a wasteful number, since it uses less digits than its factorization.
2000151131403 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 212738.
The product of its (nonzero) digits is 360, while the sum is 21.
Adding to 2000151131403 its reverse (3041311510002), we get a palindrome (5041462641405).
The spelling of 2000151131403 in words is "two trillion, one hundred fifty-one million, one hundred thirty-one thousand, four hundred three".
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