Base | Representation |
---|---|
bin | 101101100001011111110100… |
… | …100110000001100000101010 |
3 | 222020220021100012010022102111 |
4 | 231201133310212001200222 |
5 | 202220301240023031102 |
6 | 1545453013240152534 |
7 | 60112661444252611 |
oct | 5541376446014052 |
9 | 866807305108374 |
10 | 200214004111402 |
11 | 58881311830736 |
12 | 1a556994a6874a |
13 | 879413a9c93b8 |
14 | 37625a396c878 |
15 | 182305bba9cd7 |
hex | b617f498182a |
200214004111402 has 64 divisors (see below), whose sum is σ = 319005079142400. Its totient is φ = 93979002496320.
The previous prime is 200214004111327. The next prime is 200214004111411. The reversal of 200214004111402 is 204111400412002.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 5229275503 + ... + 5229313789.
It is an arithmetic number, because the mean of its divisors is an integer number (4984454361600).
Almost surely, 2200214004111402 is an apocalyptic number.
200214004111402 is a deficient number, since it is larger than the sum of its proper divisors (118791075030998).
200214004111402 is a wasteful number, since it uses less digits than its factorization.
200214004111402 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 41251.
The product of its (nonzero) digits is 512, while the sum is 22.
Adding to 200214004111402 its reverse (204111400412002), we get a palindrome (404325404523404).
The spelling of 200214004111402 in words is "two hundred trillion, two hundred fourteen billion, four million, one hundred eleven thousand, four hundred two".
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