Base | Representation |
---|---|
bin | 10111110111101… |
… | …10111111011010 |
3 | 111221210022011120 |
4 | 23323312333122 |
5 | 402230203424 |
6 | 31511510110 |
7 | 4651010223 |
oct | 1373667732 |
9 | 457708146 |
10 | 200241114 |
11 | a3038127 |
12 | 57088336 |
13 | 3263cc88 |
14 | 1c84624a |
15 | 128a5a79 |
hex | bef6fda |
200241114 has 64 divisors (see below), whose sum is σ = 448156800. Its totient is φ = 59367168.
The previous prime is 200241073. The next prime is 200241127. The reversal of 200241114 is 411142002.
It is a junction number, because it is equal to n+sod(n) for n = 200241093 and 200241102.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 121504 + ... + 123140.
It is an arithmetic number, because the mean of its divisors is an integer number (7002450).
Almost surely, 2200241114 is an apocalyptic number.
200241114 is an abundant number, since it is smaller than the sum of its proper divisors (247915686).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
200241114 is a wasteful number, since it uses less digits than its factorization.
200241114 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1727.
The product of its (nonzero) digits is 64, while the sum is 15.
The square root of 200241114 is about 14150.6577232297. The cubic root of 200241114 is about 585.0384604709.
Adding to 200241114 its reverse (411142002), we get a palindrome (611383116).
The spelling of 200241114 in words is "two hundred million, two hundred forty-one thousand, one hundred fourteen".
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