Base | Representation |
---|---|
bin | 101101100010111011001101… |
… | …010111110011111001011011 |
3 | 222021020122121202220021212010 |
4 | 231202323031113303321123 |
5 | 202223403220330301021 |
6 | 1550010042225321003 |
7 | 60123034216265361 |
oct | 5542731527637133 |
9 | 867218552807763 |
10 | 200312130322011 |
11 | 58909996493064 |
12 | 1a5719bb196163 |
13 | 87a0478251506 |
14 | 3767231bc9631 |
15 | 18258a1662976 |
hex | b62ecd5f3e5b |
200312130322011 has 32 divisors (see below), whose sum is σ = 274073607214848. Its totient is φ = 130057400309760.
The previous prime is 200312130322001. The next prime is 200312130322217. The reversal of 200312130322011 is 110223031213002.
It is not a de Polignac number, because 200312130322011 - 223 = 200312121933403 is a prime.
It is not an unprimeable number, because it can be changed into a prime (200312130322001) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 3444897240 + ... + 3444955386.
It is an arithmetic number, because the mean of its divisors is an integer number (8564800225464).
Almost surely, 2200312130322011 is an apocalyptic number.
200312130322011 is a deficient number, since it is larger than the sum of its proper divisors (73761476892837).
200312130322011 is a wasteful number, since it uses less digits than its factorization.
200312130322011 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 106491.
The product of its (nonzero) digits is 432, while the sum is 21.
Adding to 200312130322011 its reverse (110223031213002), we get a palindrome (310535161535013).
The spelling of 200312130322011 in words is "two hundred trillion, three hundred twelve billion, one hundred thirty million, three hundred twenty-two thousand, eleven".
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