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2003200212313 = 53523509914173
BaseRepresentation
bin11101001001101000000…
…010010111110101011001
321002111121110121110222001
4131021220002113311121
5230310023223243223
64132131340401001
7264504111601066
oct35115002276531
97074543543861
102003200212313
11702609329753
12284297846161
13116b93578721
146cd538d1c6d
1537193e1d9ad
hex1d268097d59

2003200212313 has 16 divisors (see below), whose sum is σ = 2045444270400. Its totient is φ = 1961122947264.

The previous prime is 2003200212271. The next prime is 2003200212331. The reversal of 2003200212313 is 3132120023002.

It is a cyclic number.

It is not a de Polignac number, because 2003200212313 - 213 = 2003200204121 is a prime.

It is a super-2 number, since 2×20032002123132 (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (2003200212113) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 141332095 + ... + 141346267.

It is an arithmetic number, because the mean of its divisors is an integer number (127840266900).

Almost surely, 22003200212313 is an apocalyptic number.

It is an amenable number.

2003200212313 is a deficient number, since it is larger than the sum of its proper divisors (42244058087).

2003200212313 is a wasteful number, since it uses less digits than its factorization.

2003200212313 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 19848.

The product of its (nonzero) digits is 432, while the sum is 19.

Adding to 2003200212313 its reverse (3132120023002), we get a palindrome (5135320235315).

The spelling of 2003200212313 in words is "two trillion, three billion, two hundred million, two hundred twelve thousand, three hundred thirteen".

Divisors: 1 53 523 5099 14173 27719 270247 751169 2666777 7412479 72268127 141339181 392861387 3830210731 37796230421 2003200212313