Base | Representation |
---|---|
bin | 11101010001000100110… |
… | …111111100110000110011 |
3 | 21010021021000000120110110 |
4 | 131101010313330300303 |
5 | 230422414223241034 |
6 | 4135533240232403 |
7 | 265206262510305 |
oct | 35210467746063 |
9 | 7107230016413 |
10 | 2011200212019 |
11 | 705a440a6959 |
12 | 28594aa6b703 |
13 | 117869abb66b |
14 | 6d4b2199975 |
15 | 374b1418de9 |
hex | 1d444dfcc33 |
2011200212019 has 32 divisors (see below), whose sum is σ = 2799730359360. Its totient is φ = 1282944268800.
The previous prime is 2011200211931. The next prime is 2011200212027. The reversal of 2011200212019 is 9102120021102.
It is not a de Polignac number, because 2011200212019 - 217 = 2011200080947 is a prime.
It is a super-2 number, since 2×20112002120192 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 2011200211986 and 2011200212004.
It is not an unprimeable number, because it can be changed into a prime (2011200212039) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 42423709 + ... + 42471089.
It is an arithmetic number, because the mean of its divisors is an integer number (87491573730).
Almost surely, 22011200212019 is an apocalyptic number.
2011200212019 is a deficient number, since it is larger than the sum of its proper divisors (788530147341).
2011200212019 is a wasteful number, since it uses less digits than its factorization.
2011200212019 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 53751.
The product of its (nonzero) digits is 144, while the sum is 21.
The spelling of 2011200212019 in words is "two trillion, eleven billion, two hundred million, two hundred twelve thousand, nineteen".
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