Base | Representation |
---|---|
bin | 11101010010010101000… |
… | …110001100011001000011 |
3 | 21010101201210120221200120 |
4 | 131102111012030121003 |
5 | 230433143301421311 |
6 | 4140314555551323 |
7 | 265254524536062 |
oct | 35222506143103 |
9 | 7111653527616 |
10 | 2012546123331 |
11 | 706574901a57 |
12 | 28606575b543 |
13 | 117a228ac9a3 |
14 | 6d59cc2c1d9 |
15 | 3753e677706 |
hex | 1d49518c643 |
2012546123331 has 16 divisors (see below), whose sum is σ = 2757895434624. Its totient is φ = 1304722024704.
The previous prime is 2012546123323. The next prime is 2012546123383. The reversal of 2012546123331 is 1333216452102.
It is not a de Polignac number, because 2012546123331 - 23 = 2012546123323 is a prime.
It is a super-2 number, since 2×20125461233312 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 2012546123292 and 2012546123301.
It is not an unprimeable number, because it can be changed into a prime (2012546127331) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 34334446 + ... + 34393011.
It is an arithmetic number, because the mean of its divisors is an integer number (172368464664).
Almost surely, 22012546123331 is an apocalyptic number.
2012546123331 is a deficient number, since it is larger than the sum of its proper divisors (745349311293).
2012546123331 is a wasteful number, since it uses less digits than its factorization.
2012546123331 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 68727730.
The product of its (nonzero) digits is 25920, while the sum is 33.
The spelling of 2012546123331 in words is "two trillion, twelve billion, five hundred forty-six million, one hundred twenty-three thousand, three hundred thirty-one".
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