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2013103331011 = 6167753879049
BaseRepresentation
bin11101010010110110010…
…011110001011011000011
321010110011122002000221001
4131102312103301123003
5230440313423043021
64140450142512431
7265304401660213
oct35226623613303
97113148060831
102013103331011
11706830392373
122861a0295717
13117ab1174a86
146d612c36243
1537573541091
hex1d4b64f16c3

2013103331011 has 16 divisors (see below), whose sum is σ = 2049734210400. Its totient is φ = 1976591335680.

The previous prime is 2013103330981. The next prime is 2013103331023. The reversal of 2013103331011 is 1101333013102.

It is a cyclic number.

It is not a de Polignac number, because 2013103331011 - 27 = 2013103330883 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 2013103331011.

It is not an unprimeable number, because it can be changed into a prime (2013103331411) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 222462415 + ... + 222471463.

It is an arithmetic number, because the mean of its divisors is an integer number (128108388150).

Almost surely, 22013103331011 is an apocalyptic number.

2013103331011 is a deficient number, since it is larger than the sum of its proper divisors (36630879389).

2013103331011 is an equidigital number, since it uses as much as digits as its factorization.

2013103331011 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 15174.

The product of its (nonzero) digits is 162, while the sum is 19.

Adding to 2013103331011 its reverse (1101333013102), we get a palindrome (3114436344113).

The spelling of 2013103331011 in words is "two trillion, thirteen billion, one hundred three million, three hundred thirty-one thousand, eleven".

Divisors: 1 61 677 5387 9049 41297 328607 551989 3646999 6126173 48746963 222466939 373696553 2973564743 33001693951 2013103331011