Base | Representation |
---|---|
bin | 101101110001100101111101… |
… | …110101110101110000001011 |
3 | 222101211000101211202121020120 |
4 | 231301211331311311300023 |
5 | 202341412043003044321 |
6 | 1552101103331354323 |
7 | 60255620040430620 |
oct | 5561457565656013 |
9 | 871730354677216 |
10 | 201320113331211 |
11 | 59168420630a16 |
12 | 1a6b522a7529a3 |
13 | 8844536391624 |
14 | 379dd34556347 |
15 | 1841be8b69ec6 |
hex | b7197dd75c0b |
201320113331211 has 32 divisors (see below), whose sum is σ = 309668020531200. Its totient is φ = 113954812605216.
The previous prime is 201320113331191. The next prime is 201320113331237. The reversal of 201320113331211 is 112133311023102.
It is not a de Polignac number, because 201320113331211 - 217 = 201320113200139 is a prime.
It is not an unprimeable number, because it can be changed into a prime (201320113331011) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 21392940 + ... + 29330838.
It is an arithmetic number, because the mean of its divisors is an integer number (9677125641600).
Almost surely, 2201320113331211 is an apocalyptic number.
201320113331211 is a gapful number since it is divisible by the number (21) formed by its first and last digit.
201320113331211 is a deficient number, since it is larger than the sum of its proper divisors (108347907199989).
201320113331211 is a wasteful number, since it uses less digits than its factorization.
201320113331211 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 7949303.
The product of its (nonzero) digits is 648, while the sum is 24.
Adding to 201320113331211 its reverse (112133311023102), we get a palindrome (313453424354313).
The spelling of 201320113331211 in words is "two hundred one trillion, three hundred twenty billion, one hundred thirteen million, three hundred thirty-one thousand, two hundred eleven".
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