Base | Representation |
---|---|
bin | 111100000001101… |
… | …0000110111011001 |
3 | 12012100220222012010 |
4 | 1320003100313121 |
5 | 13111103341213 |
6 | 531505340133 |
7 | 100624515102 |
oct | 17003206731 |
9 | 5170828163 |
10 | 2014121433 |
11 | 943a12275 |
12 | 482637649 |
13 | 26137cb3c |
14 | 1516d33a9 |
15 | bbc51ac3 |
hex | 780d0dd9 |
2014121433 has 16 divisors (see below), whose sum is σ = 2753364096. Its totient is φ = 1308869760.
The previous prime is 2014121411. The next prime is 2014121441. The reversal of 2014121433 is 3341214102.
It is not a de Polignac number, because 2014121433 - 25 = 2014121401 is a prime.
It is not an unprimeable number, because it can be changed into a prime (2014121453) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 150660 + ... + 163482.
It is an arithmetic number, because the mean of its divisors is an integer number (172085256).
Almost surely, 22014121433 is an apocalyptic number.
It is an amenable number.
2014121433 is a deficient number, since it is larger than the sum of its proper divisors (739242663).
2014121433 is a wasteful number, since it uses less digits than its factorization.
2014121433 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 14144.
The product of its (nonzero) digits is 576, while the sum is 21.
The square root of 2014121433 is about 44878.9642594390. The cubic root of 2014121433 is about 1262.8794131751.
Adding to 2014121433 its reverse (3341214102), we get a palindrome (5355335535).
The spelling of 2014121433 in words is "two billion, fourteen million, one hundred twenty-one thousand, four hundred thirty-three".
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