Base | Representation |
---|---|
bin | 101101111111110111011111… |
… | …111101011000101110010001 |
3 | 222112021210021100200212220000 |
4 | 231333313133331120232101 |
5 | 203003444433034120423 |
6 | 1554131445114440213 |
7 | 60416523444631206 |
oct | 5577673775305621 |
9 | 875253240625800 |
10 | 202301012020113 |
11 | 59506417344096 |
12 | 1a83335b733069 |
13 | 88b5b9920a206 |
14 | 37d55c7bb1cad |
15 | 185c4a84d3843 |
hex | b7fddff58b91 |
202301012020113 has 40 divisors (see below), whose sum is σ = 312497548636416. Its totient is φ = 130288205224800.
The previous prime is 202301012020109. The next prime is 202301012020117. The reversal of 202301012020113 is 311020210103202.
202301012020113 is a `hidden beast` number, since 20 + 230 + 101 + 202 + 0 + 113 = 666.
It is an interprime number because it is at equal distance from previous prime (202301012020109) and next prime (202301012020117).
It is not a de Polignac number, because 202301012020113 - 22 = 202301012020109 is a prime.
It is not an unprimeable number, because it can be changed into a prime (202301012020117) by changing a digit.
It is a polite number, since it can be written in 39 ways as a sum of consecutive naturals, for example, 69114306 + ... + 71981867.
Almost surely, 2202301012020113 is an apocalyptic number.
It is an amenable number.
202301012020113 is a deficient number, since it is larger than the sum of its proper divisors (110196536616303).
202301012020113 is a wasteful number, since it uses less digits than its factorization.
202301012020113 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 141096787 (or 141096778 counting only the distinct ones).
The product of its (nonzero) digits is 144, while the sum is 18.
Adding to 202301012020113 its reverse (311020210103202), we get a palindrome (513321222123315).
The spelling of 202301012020113 in words is "two hundred two trillion, three hundred one billion, twelve million, twenty thousand, one hundred thirteen".
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