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20434440131 = 719994915443
BaseRepresentation
bin10011000001111111…
…001100111111000011
31221202010000010001222
4103001333030333003
5313322204041011
613215404545255
71322245606130
oct230177147703
957663003058
1020434440131
118736788356
123b6355222b
131c086b71c1
14dbbc93587
157e8e83ddb
hex4c1fccfc3

20434440131 has 16 divisors (see below), whose sum is σ = 24586848000. Its totient is φ = 16590637728.

The previous prime is 20434440119. The next prime is 20434440149. The reversal of 20434440131 is 13104443402.

It is not a de Polignac number, because 20434440131 - 26 = 20434440067 is a prime.

It is a super-3 number, since 3×204344401313 (a number of 32 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 20434440131.

It is not an unprimeable number, because it can be changed into a prime (20434440161) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1315496 + ... + 1330938.

It is an arithmetic number, because the mean of its divisors is an integer number (1536678000).

Almost surely, 220434440131 is an apocalyptic number.

20434440131 is a deficient number, since it is larger than the sum of its proper divisors (4152407869).

20434440131 is a wasteful number, since it uses less digits than its factorization.

20434440131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 25418.

The product of its (nonzero) digits is 4608, while the sum is 26.

Adding to 20434440131 its reverse (13104443402), we get a palindrome (33538883533).

The spelling of 20434440131 in words is "twenty billion, four hundred thirty-four million, four hundred forty thousand, one hundred thirty-one".

Divisors: 1 7 19 133 9949 15443 69643 108101 189031 293417 1323217 2053919 153642407 1075496849 2919205733 20434440131