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2111412003433 = 43239566936241
BaseRepresentation
bin11110101110011001111…
…101100110001001101001
321110211220221012000220121
4132232121331212021221
5234043132433102213
64253545210523241
7305354520623425
oct36563175461151
97424827160817
102111412003433
11744499038a87
122a1257736521
1312414a453465
147429b3cbb85
1539dc903b88d
hex1eb99f66269

2111412003433 has 16 divisors (see below), whose sum is σ = 2169996998400. Its totient is φ = 2053261566720.

The previous prime is 2111412003341. The next prime is 2111412003461. The reversal of 2111412003433 is 3343002141112.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-2111412003433 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 2111412003398 and 2111412003407.

It is not an unprimeable number, because it can be changed into a prime (2111412003473) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 58242193 + ... + 58278433.

It is an arithmetic number, because the mean of its divisors is an integer number (135624812400).

Almost surely, 22111412003433 is an apocalyptic number.

It is an amenable number.

2111412003433 is a deficient number, since it is larger than the sum of its proper divisors (58584994967).

2111412003433 is a wasteful number, since it uses less digits than its factorization.

2111412003433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 42192.

The product of its (nonzero) digits is 1728, while the sum is 25.

Adding to 2111412003433 its reverse (3343002141112), we get a palindrome (5454414144545).

The spelling of 2111412003433 in words is "two trillion, one hundred eleven billion, four hundred twelve million, three thousand, four hundred thirty-three".

Divisors: 1 43 239 5669 10277 36241 243767 1354891 1558363 8661599 58260313 205450229 372448757 8834359847 49102604731 2111412003433