Base | Representation |
---|---|
bin | 11110101111000101011… |
… | …110101101011100001011 |
3 | 21110220210211000000001121 |
4 | 132233011132231130023 |
5 | 234101131334314311 |
6 | 4254145451300111 |
7 | 305411564443450 |
oct | 36570536553413 |
9 | 7426724000047 |
10 | 2112142104331 |
11 | 744833177656 |
12 | 2a142014a637 |
13 | 1242357a171c |
14 | 7432a35d827 |
15 | 39e1d1a7b71 |
hex | 1ebc57ad70b |
2112142104331 has 16 divisors (see below), whose sum is σ = 2415925499904. Its totient is φ = 1808871299424.
The previous prime is 2112142104299. The next prime is 2112142104341. The reversal of 2112142104331 is 1334012412112.
It is not a de Polignac number, because 2112142104331 - 25 = 2112142104299 is a prime.
It is a super-2 number, since 2×21121421043312 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 2112142104296 and 2112142104305.
It is not an unprimeable number, because it can be changed into a prime (2112142104341) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 102060021 + ... + 102080713.
It is an arithmetic number, because the mean of its divisors is an integer number (150995343744).
Almost surely, 22112142104331 is an apocalyptic number.
2112142104331 is a deficient number, since it is larger than the sum of its proper divisors (303783395573).
2112142104331 is a wasteful number, since it uses less digits than its factorization.
2112142104331 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 32370.
The product of its (nonzero) digits is 1152, while the sum is 25.
Adding to 2112142104331 its reverse (1334012412112), we get a palindrome (3446154516443).
The spelling of 2112142104331 in words is "two trillion, one hundred twelve billion, one hundred forty-two million, one hundred four thousand, three hundred thirty-one".
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