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21142103131 = 2943127133499
BaseRepresentation
bin10011101100001010…
…101110010001011011
32000120102121010012201
4103230022232101123
5321244334300011
613413524351031
71345630624432
oct235412562133
960512533181
1021142103131
118a6a191006
124120545477
131cbc1aa4c6
141047c64119
1583b16bcc1
hex4ec2ae45b

21142103131 has 16 divisors (see below), whose sum is σ = 22556160000. Its totient is φ = 19781199648.

The previous prime is 21142103119. The next prime is 21142103233. The reversal of 21142103131 is 13130124112.

It is a cyclic number.

It is not a de Polignac number, because 21142103131 - 233 = 12552168539 is a prime.

It is a super-2 number, since 2×211421031312 (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 21142103099 and 21142103108.

It is not an unprimeable number, because it can be changed into a prime (21142100131) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 91620 + ... + 225118.

It is an arithmetic number, because the mean of its divisors is an integer number (1409760000).

Almost surely, 221142103131 is an apocalyptic number.

21142103131 is a deficient number, since it is larger than the sum of its proper divisors (1414056869).

21142103131 is a wasteful number, since it uses less digits than its factorization.

21142103131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 133698.

The product of its (nonzero) digits is 144, while the sum is 19.

Adding to 21142103131 its reverse (13130124112), we get a palindrome (34272227243).

The spelling of 21142103131 in words is "twenty-one billion, one hundred forty-two million, one hundred three thousand, one hundred thirty-one".

Divisors: 1 29 43 127 1247 3683 5461 133499 158369 3871471 5740457 16954373 166473253 491676817 729038039 21142103131