Base | Representation |
---|---|
bin | 110000000100101000010110… |
… | …000110111010100100010011 |
3 | 1000201120222102010010201220022 |
4 | 300010220112012322210103 |
5 | 210202434213320240103 |
6 | 2025355013122534055 |
7 | 62350624331630432 |
oct | 6004502606724423 |
9 | 1021528363121808 |
10 | 211424431024403 |
11 | 61403663542913 |
12 | 1b86757a20732b |
13 | 90c831370220c |
14 | 3a2cdd5d17119 |
15 | 196997bdc4138 |
hex | c04a161ba913 |
211424431024403 has 16 divisors (see below), whose sum is σ = 215266741536000. Its totient is φ = 207590764157280.
The previous prime is 211424431024381. The next prime is 211424431024439. The reversal of 211424431024403 is 304420134424112.
It is a cyclic number.
It is not a de Polignac number, because 211424431024403 - 212 = 211424431020307 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (211424431024603) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 2652746648 + ... + 2652826346.
It is an arithmetic number, because the mean of its divisors is an integer number (13454171346000).
Almost surely, 2211424431024403 is an apocalyptic number.
211424431024403 is a deficient number, since it is larger than the sum of its proper divisors (3842310511597).
211424431024403 is an equidigital number, since it uses as much as digits as its factorization.
211424431024403 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 133322.
The product of its (nonzero) digits is 73728, while the sum is 35.
Adding to 211424431024403 its reverse (304420134424112), we get a palindrome (515844565448515).
The spelling of 211424431024403 in words is "two hundred eleven trillion, four hundred twenty-four billion, four hundred thirty-one million, twenty-four thousand, four hundred three".
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