Base | Representation |
---|---|
bin | 11110110001000110111… |
… | …011110101011101101010 |
3 | 21111010102011210202010121 |
4 | 132301012323311131222 |
5 | 234120103341001414 |
6 | 4255145154433454 |
7 | 305516446321462 |
oct | 36610673653552 |
9 | 7433364722117 |
10 | 2114314000234 |
11 | 745748151147 |
12 | 2a192759288a |
13 | 1244c0743027 |
14 | 744949a2ba2 |
15 | 39ee8bc2724 |
hex | 1ec46ef576a |
2114314000234 has 16 divisors (see below), whose sum is σ = 3182661847008. Its totient is φ = 1053427550032.
The previous prime is 2114314000229. The next prime is 2114314000301. The reversal of 2114314000234 is 4320004134112.
It is a junction number, because it is equal to n+sod(n) for n = 2114314000199 and 2114314000208.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 4992609 + ... + 5399515.
It is an arithmetic number, because the mean of its divisors is an integer number (198916365438).
Almost surely, 22114314000234 is an apocalyptic number.
2114314000234 is a deficient number, since it is larger than the sum of its proper divisors (1068347846774).
2114314000234 is a wasteful number, since it uses less digits than its factorization.
2114314000234 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 416069.
The product of its (nonzero) digits is 2304, while the sum is 25.
Adding to 2114314000234 its reverse (4320004134112), we get a palindrome (6434318134346).
The spelling of 2114314000234 in words is "two trillion, one hundred fourteen billion, three hundred fourteen million, two hundred thirty-four", and thus it is an aban number.
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