Base | Representation |
---|---|
bin | 110000001101001010101111… |
… | …100111011000100001010001 |
3 | 1000210200001202121201101212220 |
4 | 300031022233213120201101 |
5 | 210242042234213031001 |
6 | 2030524322002411253 |
7 | 62441204146643040 |
oct | 6015125747304121 |
9 | 1023601677641786 |
10 | 212011122002001 |
11 | 6160a459284943 |
12 | 1b941213960b29 |
13 | 913b741c5132a |
14 | 3a4d570790557 |
15 | 1979d685ecc36 |
hex | c0d2af9d8851 |
212011122002001 has 16 divisors (see below), whose sum is σ = 323080536296448. Its totient is φ = 121143224034000.
The previous prime is 212011122001981. The next prime is 212011122002063. The reversal of 212011122002001 is 100200221110212.
It is not a de Polignac number, because 212011122002001 - 27 = 212011122001873 is a prime.
It is not an unprimeable number, because it can be changed into a prime (212011122001001) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 249087475 + ... + 249937176.
It is an arithmetic number, because the mean of its divisors is an integer number (20192533518528).
Almost surely, 2212011122002001 is an apocalyptic number.
212011122002001 is a gapful number since it is divisible by the number (21) formed by its first and last digit.
It is an amenable number.
212011122002001 is a deficient number, since it is larger than the sum of its proper divisors (111069414294447).
212011122002001 is a wasteful number, since it uses less digits than its factorization.
212011122002001 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 499044892.
The product of its (nonzero) digits is 32, while the sum is 15.
Adding to 212011122002001 its reverse (100200221110212), we get a palindrome (312211343112213).
The spelling of 212011122002001 in words is "two hundred twelve trillion, eleven billion, one hundred twenty-two million, two thousand, one".
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