Base | Representation |
---|---|
bin | 1001101001111100101101… |
… | …01011011000110100110001 |
3 | 2210011210221000012000012202 |
4 | 10310332112223120310301 |
5 | 10240333231113103101 |
6 | 113054033250032545 |
7 | 4321000262144240 |
oct | 464762653306461 |
9 | 83153830160182 |
10 | 21232551300401 |
11 | 684674674a991 |
12 | 246b016578755 |
13 | bb02b46b522c |
14 | 535937996957 |
15 | 26c49265b36b |
hex | 134f96ad8d31 |
21232551300401 has 32 divisors (see below), whose sum is σ = 24361526891520. Its totient is φ = 18127678536000.
The previous prime is 21232551300329. The next prime is 21232551300439. The reversal of 21232551300401 is 10400315523212.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-21232551300401 is a prime.
It is a super-2 number, since 2×212325513004012 (a number of 27 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (21232551300461) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 9963655106 + ... + 9963657236.
It is an arithmetic number, because the mean of its divisors is an integer number (761297715360).
Almost surely, 221232551300401 is an apocalyptic number.
It is an amenable number.
21232551300401 is a deficient number, since it is larger than the sum of its proper divisors (3128975591119).
21232551300401 is a wasteful number, since it uses less digits than its factorization.
21232551300401 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 6245.
The product of its (nonzero) digits is 7200, while the sum is 29.
Adding to 21232551300401 its reverse (10400315523212), we get a palindrome (31632866823613).
The spelling of 21232551300401 in words is "twenty-one trillion, two hundred thirty-two billion, five hundred fifty-one million, three hundred thousand, four hundred one".
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