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213111201000012 = 2237415312727133923
BaseRepresentation
bin110000011101001011010001…
…011011101110101001001100
31000221120020021000102200111220
4300131023101123232221030
5210413103214424000022
62033125533441243340
762613530141101350
oct6035132133565114
91027506230380456
10213111201000012
11619a3a53192247
121ba9a466033550
1391bb3b91c8893
143a8a8cc53d460
1519987a0ea585c
hexc1d2d16eea4c

213111201000012 has 384 divisors, whose sum is σ = 600035571007488. Its totient is φ = 57608999884800.

The previous prime is 213111201000007. The next prime is 213111201000013. The reversal of 213111201000012 is 210000102111312.

213111201000012 is digitally balanced in base 2 and base 4, because in such bases it contains all the possibile digits an equal number of times.

It is a junction number, because it is equal to n+sod(n) for n = 213111200999955 and 213111201000000.

It is not an unprimeable number, because it can be changed into a prime (213111201000013) by changing a digit.

It is a polite number, since it can be written in 127 ways as a sum of consecutive naturals, for example, 6282186883 + ... + 6282220805.

It is an arithmetic number, because the mean of its divisors is an integer number (1562592632832).

Almost surely, 2213111201000012 is an apocalyptic number.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 213111201000012, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (300017785503744).

213111201000012 is an abundant number, since it is smaller than the sum of its proper divisors (386924370007476).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

213111201000012 is a wasteful number, since it uses less digits than its factorization.

213111201000012 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 34429 (or 34427 counting only the distinct ones).

The product of its (nonzero) digits is 24, while the sum is 15.

Adding to 213111201000012 its reverse (210000102111312), we get a palindrome (423111303111324).

The spelling of 213111201000012 in words is "two hundred thirteen trillion, one hundred eleven billion, two hundred one million, twelve", and thus it is an aban number.