Base | Representation |
---|---|
bin | 1001101100100101010111… |
… | …10100011101011000100010 |
3 | 2210111110122112010110012120 |
4 | 10312102223310131120202 |
5 | 10243324202140004442 |
6 | 113203410321405110 |
7 | 4330354206101046 |
oct | 466225364353042 |
9 | 83443575113176 |
10 | 21323100313122 |
11 | 68810922643a3 |
12 | 2484687199796 |
13 | bb89b51904ba |
14 | 53a087768026 |
15 | 26e9e1cd34ec |
hex | 1364abd1d622 |
21323100313122 has 16 divisors (see below), whose sum is σ = 42660921475872. Its totient is φ = 7105246629440.
The previous prime is 21323100313111. The next prime is 21323100313129. The reversal of 21323100313122 is 22131300132312.
It is a super-3 number, since 3×213231003131223 (a number of 41 digits) contains 333 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 21323100313092 and 21323100313101.
It is not an unprimeable number, because it can be changed into a prime (21323100313129) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 613349904 + ... + 613384667.
It is an arithmetic number, because the mean of its divisors is an integer number (2666307592242).
Almost surely, 221323100313122 is an apocalyptic number.
21323100313122 is an abundant number, since it is smaller than the sum of its proper divisors (21337821162750).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
21323100313122 is a wasteful number, since it uses less digits than its factorization.
21323100313122 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1226737473.
The product of its (nonzero) digits is 1296, while the sum is 24.
Adding to 21323100313122 its reverse (22131300132312), we get a palindrome (43454400445434).
The spelling of 21323100313122 in words is "twenty-one trillion, three hundred twenty-three billion, one hundred million, three hundred thirteen thousand, one hundred twenty-two".
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