Base | Representation |
---|---|
bin | 110000100000010001100011… |
… | …110111111000110001001010 |
3 | 1000222022120211002122011002212 |
4 | 300200101203313320301022 |
5 | 210430100234440040204 |
6 | 2033411424355025122 |
7 | 62635105225301531 |
oct | 6040214367706112 |
9 | 1028276732564085 |
10 | 213324111252554 |
11 | 61a7627a4aa245 |
12 | 1bb1378529b1a2 |
13 | 92054ba125733 |
14 | 3a96d290a7318 |
15 | 199e0b2a4ec6e |
hex | c20463df8c4a |
213324111252554 has 16 divisors (see below), whose sum is σ = 337631428461600. Its totient is φ = 100807097911344.
The previous prime is 213324111252541. The next prime is 213324111252557. The reversal of 213324111252554 is 455252111423312.
It is a super-3 number, since 3×2133241112525543 (a number of 44 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is not an unprimeable number, because it can be changed into a prime (213324111252557) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 6699020357 + ... + 6699052200.
It is an arithmetic number, because the mean of its divisors is an integer number (21101964278850).
Almost surely, 2213324111252554 is an apocalyptic number.
213324111252554 is a deficient number, since it is larger than the sum of its proper divisors (124307317209046).
213324111252554 is a wasteful number, since it uses less digits than its factorization.
213324111252554 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 13398072997.
The product of its digits is 288000, while the sum is 41.
Adding to 213324111252554 its reverse (455252111423312), we get a palindrome (668576222675866).
The spelling of 213324111252554 in words is "two hundred thirteen trillion, three hundred twenty-four billion, one hundred eleven million, two hundred fifty-two thousand, five hundred fifty-four".
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