Base | Representation |
---|---|
bin | 1001101101011000101011… |
… | …00111001110100110111011 |
3 | 2210121002202011101012222210 |
4 | 10312230111213032212323 |
5 | 10244302110112032103 |
6 | 113224203444350203 |
7 | 4332350613256020 |
oct | 466542547164673 |
9 | 83532664335883 |
10 | 21350645033403 |
11 | 6891837569434 |
12 | 2489a939a5363 |
13 | bbb48498335a |
14 | 53b53ba83547 |
15 | 2705a50b6e03 |
hex | 136b159ce9bb |
21350645033403 has 16 divisors (see below), whose sum is σ = 32699465061120. Its totient is φ = 12138437783136.
The previous prime is 21350645033381. The next prime is 21350645033429. The reversal of 21350645033403 is 30433054605312.
It is not a de Polignac number, because 21350645033403 - 28 = 21350645033147 is a prime.
It is a super-3 number, since 3×213506450334033 (a number of 41 digits) contains 333 as substring.
It is not an unprimeable number, because it can be changed into a prime (21350645033603) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 2580446073 + ... + 2580454346.
It is an arithmetic number, because the mean of its divisors is an integer number (2043716566320).
Almost surely, 221350645033403 is an apocalyptic number.
21350645033403 is a deficient number, since it is larger than the sum of its proper divisors (11348820027717).
21350645033403 is a wasteful number, since it uses less digits than its factorization.
21350645033403 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 5160900626.
The product of its (nonzero) digits is 388800, while the sum is 39.
Adding to 21350645033403 its reverse (30433054605312), we get a palindrome (51783699638715).
The spelling of 21350645033403 in words is "twenty-one trillion, three hundred fifty billion, six hundred forty-five million, thirty-three thousand, four hundred three".
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