Base | Representation |
---|---|
bin | 1001101110110100110101… |
… | …01000101000001001010011 |
3 | 2210202211110020220120112010 |
4 | 10313122122220220021103 |
5 | 10301104422040111011 |
6 | 113303025143034003 |
7 | 4336051646445222 |
oct | 467323250501123 |
9 | 83684406816463 |
10 | 21400121410131 |
11 | 69008166aa582 |
12 | 24975a143b903 |
13 | bc303b0b9609 |
14 | 53dab2a2ccb9 |
15 | 2719ed9c91a6 |
hex | 13769aa28253 |
21400121410131 has 32 divisors (see below), whose sum is σ = 30476824934400. Its totient is φ = 13327274499840.
The previous prime is 21400121410097. The next prime is 21400121410147. The reversal of 21400121410131 is 13101412100412.
It is not a de Polignac number, because 21400121410131 - 238 = 21125243503187 is a prime.
It is a super-2 number, since 2×214001214101312 (a number of 27 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 21400121410098 and 21400121410107.
It is not an unprimeable number, because it can be changed into a prime (21400121410531) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 10432440 + ... + 12314058.
It is an arithmetic number, because the mean of its divisors is an integer number (952400779200).
Almost surely, 221400121410131 is an apocalyptic number.
21400121410131 is a deficient number, since it is larger than the sum of its proper divisors (9076703524269).
21400121410131 is a wasteful number, since it uses less digits than its factorization.
21400121410131 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1885899.
The product of its (nonzero) digits is 192, while the sum is 21.
Adding to 21400121410131 its reverse (13101412100412), we get a palindrome (34501533510543).
The spelling of 21400121410131 in words is "twenty-one trillion, four hundred billion, one hundred twenty-one million, four hundred ten thousand, one hundred thirty-one".
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