Base | Representation |
---|---|
bin | 11111001001101010111… |
… | …010111101001101001010 |
3 | 21120122111012022001121022 |
4 | 133021222322331031022 |
5 | 240033112003201404 |
6 | 4315230203312442 |
7 | 310442142656060 |
oct | 37115272751512 |
9 | 7518435261538 |
10 | 2140687553354 |
11 | 755951352a39 |
12 | 2a6a67b1b722 |
13 | 126b346c836c |
14 | 75877536030 |
15 | 3aa3e2638be |
hex | 1f26aebd34a |
2140687553354 has 32 divisors (see below), whose sum is σ = 3869957061120. Its totient is φ = 867562336368.
The previous prime is 2140687553269. The next prime is 2140687553363. The reversal of 2140687553354 is 4533557860412.
It is a junction number, because it is equal to n+sod(n) for n = 2140687553296 and 2140687553305.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 7210712 + ... + 7501715.
It is an arithmetic number, because the mean of its divisors is an integer number (120936158160).
Almost surely, 22140687553354 is an apocalyptic number.
2140687553354 is a deficient number, since it is larger than the sum of its proper divisors (1729269507766).
2140687553354 is a wasteful number, since it uses less digits than its factorization.
2140687553354 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 14713002.
The product of its (nonzero) digits is 12096000, while the sum is 53.
The spelling of 2140687553354 in words is "two trillion, one hundred forty billion, six hundred eighty-seven million, five hundred fifty-three thousand, three hundred fifty-four".
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