Base | Representation |
---|---|
bin | 1100011110110110100… |
… | …0000100000100010001 |
3 | 202111111200212202221010 |
4 | 3013231220010010101 |
5 | 12003133131200423 |
6 | 242302403321133 |
7 | 21331011530151 |
oct | 3075550040421 |
9 | 674450782833 |
10 | 214440100113 |
11 | 82a41934138 |
12 | 356876801a9 |
13 | 172b5b6c905 |
14 | a543bda761 |
15 | 58a103c693 |
hex | 31eda04111 |
214440100113 has 16 divisors (see below), whose sum is σ = 292101707520. Its totient is φ = 139901309184.
The previous prime is 214440100109. The next prime is 214440100141. The reversal of 214440100113 is 311001044412.
It is not a de Polignac number, because 214440100113 - 22 = 214440100109 is a prime.
It is a super-5 number, since 5×2144401001135 (a number of 58 digits) contains 55555 as substring. Note that it is a super-d number also for d = 2.
It is a self number, because there is not a number n which added to its sum of digits gives 214440100113.
It is not an unprimeable number, because it can be changed into a prime (214440100153) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 3976806 + ... + 4030367.
It is an arithmetic number, because the mean of its divisors is an integer number (18256356720).
Almost surely, 2214440100113 is an apocalyptic number.
It is an amenable number.
214440100113 is a deficient number, since it is larger than the sum of its proper divisors (77661607407).
214440100113 is a wasteful number, since it uses less digits than its factorization.
214440100113 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 8007368.
The product of its (nonzero) digits is 384, while the sum is 21.
Adding to 214440100113 its reverse (311001044412), we get a palindrome (525441144525).
The spelling of 214440100113 in words is "two hundred fourteen billion, four hundred forty million, one hundred thousand, one hundred thirteen".
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