Base | Representation |
---|---|
bin | 11111010010011110100… |
… | …110000001000101010010 |
3 | 21121112220021001100122120 |
4 | 133102132212001011102 |
5 | 240211443432222114 |
6 | 4323432424515110 |
7 | 311225403652341 |
oct | 37223646010522 |
9 | 7545807040576 |
10 | 2150144414034 |
11 | 759964516381 |
12 | 2a886701ba96 |
13 | 1279b0a08006 |
14 | 760d34b3b58 |
15 | 3ade45d65a9 |
hex | 1f49e981152 |
2150144414034 has 16 divisors (see below), whose sum is σ = 4300376820960. Its totient is φ = 716700139200.
The previous prime is 2150144414023. The next prime is 2150144414057. The reversal of 2150144414034 is 4304144410512.
It is a super-3 number, since 3×21501444140343 (a number of 38 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a junction number, because it is equal to n+sod(n) for n = 2150144413986 and 2150144414004.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 3346564 + ... + 3936975.
It is an arithmetic number, because the mean of its divisors is an integer number (268773551310).
Almost surely, 22150144414034 is an apocalyptic number.
2150144414034 is an abundant number, since it is smaller than the sum of its proper divisors (2150232406926).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
2150144414034 is a wasteful number, since it uses less digits than its factorization.
2150144414034 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 7332745.
The product of its (nonzero) digits is 30720, while the sum is 33.
Adding to 2150144414034 its reverse (4304144410512), we get a palindrome (6454288824546).
The spelling of 2150144414034 in words is "two trillion, one hundred fifty billion, one hundred forty-four million, four hundred fourteen thousand, thirty-four".
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