Base | Representation |
---|---|
bin | 11111010101101001110… |
… | …101000100100101101001 |
3 | 21121212200220001011001010 |
4 | 133111221311010211221 |
5 | 240240434324313101 |
6 | 4325155031014133 |
7 | 311406036056064 |
oct | 37255165044551 |
9 | 7555626034033 |
10 | 2153554135401 |
11 | 760354191519 |
12 | 2a9458b0a349 |
13 | 128105255916 |
14 | 763382918db |
15 | 3b043b0e2d6 |
hex | 1f569d44969 |
2153554135401 has 32 divisors (see below), whose sum is σ = 2918295705600. Its totient is φ = 1412479010880.
The previous prime is 2153554135361. The next prime is 2153554135423. The reversal of 2153554135401 is 1045314553512.
It is not a de Polignac number, because 2153554135401 - 29 = 2153554134889 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 2153554135401.
It is not an unprimeable number, because it can be changed into a prime (2153554135301) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 27079386 + ... + 27158796.
It is an arithmetic number, because the mean of its divisors is an integer number (91196740800).
Almost surely, 22153554135401 is an apocalyptic number.
It is an amenable number.
2153554135401 is a deficient number, since it is larger than the sum of its proper divisors (764741570199).
2153554135401 is a wasteful number, since it uses less digits than its factorization.
2153554135401 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 80109.
The product of its (nonzero) digits is 180000, while the sum is 39.
Adding to 2153554135401 its reverse (1045314553512), we get a palindrome (3198868688913).
The spelling of 2153554135401 in words is "two trillion, one hundred fifty-three billion, five hundred fifty-four million, one hundred thirty-five thousand, four hundred one".
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