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2200113232131 = 32693781172103
BaseRepresentation
bin100000000001000000111…
…101111011100100000011
321210022212200012022202010
4200001000331323210003
5242021312441412011
64402415034024003
7314644566624633
oct40010075734403
97708780168663
102200113232131
11779076620a61
122b6491578003
1312c61517aab9
14786b3a086c3
153c36b36c1a6
hex20040f7b903

2200113232131 has 16 divisors (see below), whose sum is σ = 2944508163840. Its totient is φ = 1461230668320.

The previous prime is 2200113232117. The next prime is 2200113232153. The reversal of 2200113232131 is 1312323110022.

It is not a de Polignac number, because 2200113232131 - 27 = 2200113232003 is a prime.

It is a super-2 number, since 2×22001132321312 (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 2200113232098 and 2200113232107.

It is not an unprimeable number, because it can be changed into a prime (2200113232831) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 30477426 + ... + 30549528.

It is an arithmetic number, because the mean of its divisors is an integer number (184031760240).

Almost surely, 22200113232131 is an apocalyptic number.

2200113232131 is a deficient number, since it is larger than the sum of its proper divisors (744394931709).

2200113232131 is a wasteful number, since it uses less digits than its factorization.

2200113232131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 110186.

The product of its (nonzero) digits is 432, while the sum is 21.

Adding to 2200113232131 its reverse (1312323110022), we get a palindrome (3512436342153).

The spelling of 2200113232131 in words is "two trillion, two hundred billion, one hundred thirteen million, two hundred thirty-two thousand, one hundred thirty-one".

Divisors: 1 3 269 807 37811 72103 113433 216309 10171159 19395707 30513477 58187121 2726286533 8178859599 733371077377 2200113232131