Base | Representation |
---|---|
bin | 100000000001000000111… |
… | …101111011100100000011 |
3 | 21210022212200012022202010 |
4 | 200001000331323210003 |
5 | 242021312441412011 |
6 | 4402415034024003 |
7 | 314644566624633 |
oct | 40010075734403 |
9 | 7708780168663 |
10 | 2200113232131 |
11 | 779076620a61 |
12 | 2b6491578003 |
13 | 12c61517aab9 |
14 | 786b3a086c3 |
15 | 3c36b36c1a6 |
hex | 20040f7b903 |
2200113232131 has 16 divisors (see below), whose sum is σ = 2944508163840. Its totient is φ = 1461230668320.
The previous prime is 2200113232117. The next prime is 2200113232153. The reversal of 2200113232131 is 1312323110022.
It is not a de Polignac number, because 2200113232131 - 27 = 2200113232003 is a prime.
It is a super-2 number, since 2×22001132321312 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 2200113232098 and 2200113232107.
It is not an unprimeable number, because it can be changed into a prime (2200113232831) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 30477426 + ... + 30549528.
It is an arithmetic number, because the mean of its divisors is an integer number (184031760240).
Almost surely, 22200113232131 is an apocalyptic number.
2200113232131 is a deficient number, since it is larger than the sum of its proper divisors (744394931709).
2200113232131 is a wasteful number, since it uses less digits than its factorization.
2200113232131 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 110186.
The product of its (nonzero) digits is 432, while the sum is 21.
Adding to 2200113232131 its reverse (1312323110022), we get a palindrome (3512436342153).
The spelling of 2200113232131 in words is "two trillion, two hundred billion, one hundred thirteen million, two hundred thirty-two thousand, one hundred thirty-one".
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