Base | Representation |
---|---|
bin | 1010000110011101010001… |
… | …11111101001000111101011 |
3 | 2220122110100012211212120000 |
4 | 11003032220333221013223 |
5 | 10402410400423042103 |
6 | 115124034125034043 |
7 | 4451525551343646 |
oct | 503165077510753 |
9 | 86573305755500 |
10 | 22212111143403 |
11 | 7094115743345 |
12 | 25a8a330b5923 |
13 | c517930446cc |
14 | 56b10149ca5d |
15 | 287bc46aeaa3 |
hex | 1433a8fe91eb |
22212111143403 has 20 divisors (see below), whose sum is σ = 33181250985960. Its totient is φ = 14807986594272.
The previous prime is 22212111143371. The next prime is 22212111143407. The reversal of 22212111143403 is 30434111121222.
22212111143403 is a `hidden beast` number, since 2 + 2 + 2 + 1 + 2 + 111 + 143 + 403 = 666.
It is not a de Polignac number, because 22212111143403 - 25 = 22212111143371 is a prime.
It is a Harshad number since it is a multiple of its sum of digits (27).
It is not an unprimeable number, because it can be changed into a prime (22212111143407) by changing a digit.
It is a polite number, since it can be written in 19 ways as a sum of consecutive naturals, for example, 14835928 + ... + 16264346.
It is an arithmetic number, because the mean of its divisors is an integer number (1659062549298).
Almost surely, 222212111143403 is an apocalyptic number.
22212111143403 is a deficient number, since it is larger than the sum of its proper divisors (10969139842557).
22212111143403 is a wasteful number, since it uses less digits than its factorization.
22212111143403 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1620408 (or 1620399 counting only the distinct ones).
The product of its (nonzero) digits is 2304, while the sum is 27.
Adding to 22212111143403 its reverse (30434111121222), we get a palindrome (52646222264625).
The spelling of 22212111143403 in words is "twenty-two trillion, two hundred twelve billion, one hundred eleven million, one hundred forty-three thousand, four hundred three".
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