Base | Representation |
---|---|
bin | 110011001010010110000111… |
… | …011101001011100110100011 |
3 | 1002111200212112100221211121112 |
4 | 303022112013131023212203 |
5 | 213443041132421302003 |
6 | 2114320434251413535 |
7 | 65252350061520650 |
oct | 6312260735134643 |
9 | 1074625470854545 |
10 | 225011314244003 |
11 | 65771842948921 |
12 | 212a0849a542ab |
13 | 98726256a87c1 |
14 | 3d7c86a138c27 |
15 | 1b030d9aaa3d8 |
hex | cca58774b9a3 |
225011314244003 has 16 divisors (see below), whose sum is σ = 264951321891840. Its totient is φ = 187092819344256.
The previous prime is 225011314243999. The next prime is 225011314244011. The reversal of 225011314244003 is 300442413110522.
It is not a de Polignac number, because 225011314244003 - 22 = 225011314243999 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (225011314244023) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 3026179493 + ... + 3026253846.
It is an arithmetic number, because the mean of its divisors is an integer number (16559457618240).
Almost surely, 2225011314244003 is an apocalyptic number.
225011314244003 is a deficient number, since it is larger than the sum of its proper divisors (39940007647837).
225011314244003 is a wasteful number, since it uses less digits than its factorization.
225011314244003 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 6052433506.
The product of its (nonzero) digits is 23040, while the sum is 32.
Adding to 225011314244003 its reverse (300442413110522), we get a palindrome (525453727354525).
The spelling of 225011314244003 in words is "two hundred twenty-five trillion, eleven billion, three hundred fourteen million, two hundred forty-four thousand, three".
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