Base | Representation |
---|---|
bin | 1000100111011101… |
… | …1100000011101001 |
3 | 12222012100011012010 |
4 | 2021313130003221 |
5 | 14214112331213 |
6 | 1021303510133 |
7 | 111214162365 |
oct | 21167340351 |
9 | 5865304163 |
10 | 2313011433 |
11 | a876a87a7 |
12 | 546758349 |
13 | 2ab27c625 |
14 | 17d2982a5 |
15 | d80e1ac3 |
hex | 89ddc0e9 |
2313011433 has 16 divisors (see below), whose sum is σ = 3168398016. Its totient is φ = 1500034560.
The previous prime is 2313011429. The next prime is 2313011443. The reversal of 2313011433 is 3341103132.
2313011433 is digitally balanced in base 2 and base 4, because in such bases it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 2313011433 - 22 = 2313011429 is a prime.
It is not an unprimeable number, because it can be changed into a prime (2313011443) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 15585 + ... + 69777.
It is an arithmetic number, because the mean of its divisors is an integer number (198024876).
Almost surely, 22313011433 is an apocalyptic number.
It is an amenable number.
2313011433 is a deficient number, since it is larger than the sum of its proper divisors (855386583).
2313011433 is a wasteful number, since it uses less digits than its factorization.
2313011433 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 54584.
The product of its (nonzero) digits is 648, while the sum is 21.
The square root of 2313011433 is about 48093.7774873216. Note that the first 3 decimals coincide. The cubic root of 2313011433 is about 1322.4905979037.
Adding to 2313011433 its reverse (3341103132), we get a palindrome (5654114565).
The spelling of 2313011433 in words is "two billion, three hundred thirteen million, eleven thousand, four hundred thirty-three".
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