Base | Representation |
---|---|
bin | 1010101001011100110100… |
… | …01101110110110011110011 |
3 | 10001220101210120011011211212 |
4 | 11110232122031312303303 |
5 | 11032110300214213011 |
6 | 121444241322230335 |
7 | 4634431666431350 |
oct | 524563215666363 |
9 | 101811716134755 |
10 | 23414454054131 |
11 | 7508017999998 |
12 | 2761a653553ab |
13 | 100ac86b49c0a |
14 | 5ad3a0c25627 |
15 | 2a90e4de608b |
hex | 154b9a376cf3 |
23414454054131 has 16 divisors (see below), whose sum is σ = 27277484544000. Its totient is φ = 19684022476608.
The previous prime is 23414454054127. The next prime is 23414454054139. The reversal of 23414454054131 is 13145045441432.
It is not a de Polignac number, because 23414454054131 - 22 = 23414454054127 is a prime.
It is a super-2 number, since 2×234144540541312 (a number of 28 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (23414454054139) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 127899731 + ... + 128082668.
It is an arithmetic number, because the mean of its divisors is an integer number (1704842784000).
Almost surely, 223414454054131 is an apocalyptic number.
23414454054131 is a deficient number, since it is larger than the sum of its proper divisors (3863030489869).
23414454054131 is a wasteful number, since it uses less digits than its factorization.
23414454054131 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 255982658.
The product of its (nonzero) digits is 460800, while the sum is 41.
Adding to 23414454054131 its reverse (13145045441432), we get a palindrome (36559499495563).
The spelling of 23414454054131 in words is "twenty-three trillion, four hundred fourteen billion, four hundred fifty-four million, fifty-four thousand, one hundred thirty-one".
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