Base | Representation |
---|---|
bin | 100011000101100010000… |
… | …001001011111110001011 |
3 | 22112111112011210020020120 |
4 | 203011202001023332023 |
5 | 304000434002201103 |
6 | 5043353113354323 |
7 | 336124554314505 |
oct | 43054201137613 |
9 | 8474464706216 |
10 | 2411121131403 |
11 | 84a607025876 |
12 | 32b35b7089a3 |
13 | 1464a1c2bc2a |
14 | 849ada54d75 |
15 | 42abade1253 |
hex | 2316204bf8b |
2411121131403 has 16 divisors (see below), whose sum is σ = 3320389579776. Its totient is φ = 1554691425120.
The previous prime is 2411121131399. The next prime is 2411121131467. The reversal of 2411121131403 is 3041311211142.
It is not a de Polignac number, because 2411121131403 - 22 = 2411121131399 is a prime.
It is a super-2 number, since 2×24111211314032 (a number of 26 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (2411121131483) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 7087876 + ... + 7420257.
It is an arithmetic number, because the mean of its divisors is an integer number (207524348736).
Almost surely, 22411121131403 is an apocalyptic number.
2411121131403 is a deficient number, since it is larger than the sum of its proper divisors (909268448373).
2411121131403 is a wasteful number, since it uses less digits than its factorization.
2411121131403 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 14509954.
The product of its (nonzero) digits is 576, while the sum is 24.
Adding to 2411121131403 its reverse (3041311211142), we get a palindrome (5452432342545).
The spelling of 2411121131403 in words is "two trillion, four hundred eleven billion, one hundred twenty-one million, one hundred thirty-one thousand, four hundred three".
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