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243130003041 = 3503357145119
BaseRepresentation
bin1110001001101110101…
…1010110111001100001
3212020120010222211222110
43202123223112321201
512440412240044131
6303405315425533
723364662633052
oct3423353267141
9766503884873
10243130003041
1194124603912
123b1538b52a9
1319c089a2c33
14baa6256729
1564ceb2e646
hex389bad6e61

243130003041 has 16 divisors (see below), whose sum is σ = 324915978240. Its totient is φ = 161715545040.

The previous prime is 243130003007. The next prime is 243130003049. The reversal of 243130003041 is 140300031342.

It is not a de Polignac number, because 243130003041 - 215 = 243129970273 is a prime.

It is a super-2 number, since 2×2431300030412 (a number of 24 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 243130002999 and 243130003017.

It is not an unprimeable number, because it can be changed into a prime (243130003049) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 5366080 + ... + 5411198.

It is an arithmetic number, because the mean of its divisors is an integer number (20307248640).

Almost surely, 2243130003041 is an apocalyptic number.

It is an amenable number.

243130003041 is a deficient number, since it is larger than the sum of its proper divisors (81785975199).

243130003041 is a wasteful number, since it uses less digits than its factorization.

243130003041 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 49196.

The product of its (nonzero) digits is 864, while the sum is 21.

Adding to 243130003041 its reverse (140300031342), we get a palindrome (383430034383).

The spelling of 243130003041 in words is "two hundred forty-three billion, one hundred thirty million, three thousand, forty-one".

Divisors: 1 3 503 1509 3571 10713 45119 135357 1796213 5388639 22694857 68084571 161119949 483359847 81043334347 243130003041