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244030021113 = 35314563105389
BaseRepresentation
bin1110001101000101010…
…0101001110111111001
3212022212212112111200010
43203101110221313321
512444233141133423
6304034510132133
723426201645334
oct3432124516771
9768785474603
10244030021113
11945466487aa
123b3651b1049
131a0202a48c8
14bb4d9b961b
156533b61693
hex38d1529df9

244030021113 has 16 divisors (see below), whose sum is σ = 331538391360. Its totient is φ = 159604645824.

The previous prime is 244030021051. The next prime is 244030021129. The reversal of 244030021113 is 311120030442.

It is not a de Polignac number, because 244030021113 - 213 = 244030012921 is a prime.

It is a super-2 number, since 2×2440300211132 (a number of 24 digits) contains 22 as substring.

It is a Curzon number.

It is a self number, because there is not a number n which added to its sum of digits gives 244030021113.

It is not an unprimeable number, because it can be changed into a prime (244030021133) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 2262823 + ... + 2368211.

It is an arithmetic number, because the mean of its divisors is an integer number (20721149460).

Almost surely, 2244030021113 is an apocalyptic number.

It is an amenable number.

244030021113 is a deficient number, since it is larger than the sum of its proper divisors (87508370247).

244030021113 is a wasteful number, since it uses less digits than its factorization.

244030021113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 120008.

The product of its (nonzero) digits is 576, while the sum is 21.

Adding to 244030021113 its reverse (311120030442), we get a palindrome (555150051555).

The spelling of 244030021113 in words is "two hundred forty-four billion, thirty million, twenty-one thousand, one hundred thirteen".

Divisors: 1 3 53 159 14563 43689 105389 316167 771839 2315517 5585617 16756851 1534780007 4604340021 81343340371 244030021113