Base | Representation |
---|---|
bin | 1110001101000101010… |
… | …0101001110111111001 |
3 | 212022212212112111200010 |
4 | 3203101110221313321 |
5 | 12444233141133423 |
6 | 304034510132133 |
7 | 23426201645334 |
oct | 3432124516771 |
9 | 768785474603 |
10 | 244030021113 |
11 | 945466487aa |
12 | 3b3651b1049 |
13 | 1a0202a48c8 |
14 | bb4d9b961b |
15 | 6533b61693 |
hex | 38d1529df9 |
244030021113 has 16 divisors (see below), whose sum is σ = 331538391360. Its totient is φ = 159604645824.
The previous prime is 244030021051. The next prime is 244030021129. The reversal of 244030021113 is 311120030442.
It is not a de Polignac number, because 244030021113 - 213 = 244030012921 is a prime.
It is a super-2 number, since 2×2440300211132 (a number of 24 digits) contains 22 as substring.
It is a Curzon number.
It is a self number, because there is not a number n which added to its sum of digits gives 244030021113.
It is not an unprimeable number, because it can be changed into a prime (244030021133) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 2262823 + ... + 2368211.
It is an arithmetic number, because the mean of its divisors is an integer number (20721149460).
Almost surely, 2244030021113 is an apocalyptic number.
It is an amenable number.
244030021113 is a deficient number, since it is larger than the sum of its proper divisors (87508370247).
244030021113 is a wasteful number, since it uses less digits than its factorization.
244030021113 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 120008.
The product of its (nonzero) digits is 576, while the sum is 21.
Adding to 244030021113 its reverse (311120030442), we get a palindrome (555150051555).
The spelling of 244030021113 in words is "two hundred forty-four billion, thirty million, twenty-one thousand, one hundred thirteen".
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