Base | Representation |
---|---|
bin | 1011010111111111010110… |
… | …01111110001001100000001 |
3 | 10021120021022201000011220020 |
4 | 11223333223033301030001 |
5 | 11234310213041002001 |
6 | 125111021240404053 |
7 | 5161111605222060 |
oct | 553775317611401 |
9 | 107507281004806 |
10 | 25013541344001 |
11 | 7a74201a94791 |
12 | 297b960476629 |
13 | 10c59c7949292 |
14 | 62693a2081d7 |
15 | 2d59d62dc736 |
hex | 16bfeb3f1301 |
25013541344001 has 32 divisors (see below), whose sum is σ = 38153581382400. Its totient is φ = 14279313657600.
The previous prime is 25013541343969. The next prime is 25013541344003. The reversal of 25013541344001 is 10044314531052.
It is not a de Polignac number, because 25013541344001 - 25 = 25013541343969 is a prime.
It is a Curzon number.
It is not an unprimeable number, because it can be changed into a prime (25013541344003) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 309912951 + ... + 309993651.
It is an arithmetic number, because the mean of its divisors is an integer number (1192299418200).
Almost surely, 225013541344001 is an apocalyptic number.
25013541344001 is a gapful number since it is divisible by the number (21) formed by its first and last digit.
It is an amenable number.
25013541344001 is a deficient number, since it is larger than the sum of its proper divisors (13140040038399).
25013541344001 is a wasteful number, since it uses less digits than its factorization.
25013541344001 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 95129.
The product of its (nonzero) digits is 28800, while the sum is 33.
Adding to 25013541344001 its reverse (10044314531052), we get a palindrome (35057855875053).
The spelling of 25013541344001 in words is "twenty-five trillion, thirteen billion, five hundred forty-one million, three hundred forty-four thousand, one".
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