Base | Representation |
---|---|
bin | 1110110000000000011… |
… | …1110111110101001001 |
3 | 220020002020110121001000 |
4 | 3230000013313311021 |
5 | 13122433203243103 |
6 | 312225051245213 |
7 | 24210421046403 |
oct | 3540007676511 |
9 | 806066417030 |
10 | 253405134153 |
11 | 98517656a06 |
12 | 41140a49809 |
13 | 1ab85691882 |
14 | c39cb57b73 |
15 | 68d1c37aa3 |
hex | 3b001f7d49 |
253405134153 has 16 divisors (see below), whose sum is σ = 383402568960. Its totient is φ = 165342356208.
The previous prime is 253405134109. The next prime is 253405134161. The reversal of 253405134153 is 351431504352.
253405134153 is a `hidden beast` number, since 2 + 53 + 4 + 0 + 513 + 41 + 53 = 666.
253405134153 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 253405134153 - 214 = 253405117769 is a prime.
It is not an unprimeable number, because it can be changed into a prime (253405134253) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 99843150 + ... + 99845687.
It is an arithmetic number, because the mean of its divisors is an integer number (23962660560).
Almost surely, 2253405134153 is an apocalyptic number.
It is an amenable number.
253405134153 is a deficient number, since it is larger than the sum of its proper divisors (129997434807).
253405134153 is a wasteful number, since it uses less digits than its factorization.
253405134153 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 199688893 (or 199688887 counting only the distinct ones).
The product of its (nonzero) digits is 108000, while the sum is 36.
The spelling of 253405134153 in words is "two hundred fifty-three billion, four hundred five million, one hundred thirty-four thousand, one hundred fifty-three".
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