Base | Representation |
---|---|
bin | 111001111111011000100001… |
… | …101111101010101110111001 |
3 | 1020110000222221202201201212000 |
4 | 321333120201233222232321 |
5 | 231412121223403140001 |
6 | 2302233423532411213 |
7 | 104502225601413465 |
oct | 7177304157525671 |
9 | 1213028852651760 |
10 | 255044314115001 |
11 | 742a0760365434 |
12 | 24731368916b09 |
13 | ac4076384a728 |
14 | 46da2d41014a5 |
15 | 1e7444ba28a86 |
hex | e7f621beabb9 |
255044314115001 has 32 divisors (see below), whose sum is σ = 378815924256000. Its totient is φ = 169592148278784.
The previous prime is 255044314114981. The next prime is 255044314115011. The reversal of 255044314115001 is 100511413440552.
255044314115001 is a `hidden beast` number, since 2 + 5 + 5 + 0 + 4 + 4 + 3 + 141 + 1 + 500 + 1 = 666.
It is not a de Polignac number, because 255044314115001 - 211 = 255044314112953 is a prime.
It is not an unprimeable number, because it can be changed into a prime (255044314115011) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 36995241 + ... + 43344393.
It is an arithmetic number, because the mean of its divisors is an integer number (11837997633000).
Almost surely, 2255044314115001 is an apocalyptic number.
It is an amenable number.
255044314115001 is a deficient number, since it is larger than the sum of its proper divisors (123771610140999).
255044314115001 is a wasteful number, since it uses less digits than its factorization.
255044314115001 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 6352990 (or 6352984 counting only the distinct ones).
The product of its (nonzero) digits is 48000, while the sum is 36.
Adding to 255044314115001 its reverse (100511413440552), we get a palindrome (355555727555553).
The spelling of 255044314115001 in words is "two hundred fifty-five trillion, forty-four billion, three hundred fourteen million, one hundred fifteen thousand, one".
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