Base | Representation |
---|---|
bin | 1011101001001101000001… |
… | …11111110011100011010001 |
3 | 10100122210222112221112021012 |
4 | 11310212200333303203101 |
5 | 11324003020242212431 |
6 | 130242435232340305 |
7 | 5251620540403406 |
oct | 564464077634321 |
9 | 110583875845235 |
10 | 25605001132241 |
11 | 8182024688833 |
12 | 2a565070a4695 |
13 | 113970616c53b |
14 | 6474081622ad |
15 | 2e60a150222b |
hex | 1749a0ff38d1 |
25605001132241 has 16 divisors (see below), whose sum is σ = 27122914022400. Its totient is φ = 24104389824000.
The previous prime is 25605001132237. The next prime is 25605001132261. The reversal of 25605001132241 is 14223110050652.
It is not a de Polignac number, because 25605001132241 - 22 = 25605001132237 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 25605001132198 and 25605001132207.
It is not an unprimeable number, because it can be changed into a prime (25605001132261) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 426110 + ... + 7168791.
It is an arithmetic number, because the mean of its divisors is an integer number (1695182126400).
Almost surely, 225605001132241 is an apocalyptic number.
It is an amenable number.
25605001132241 is a deficient number, since it is larger than the sum of its proper divisors (1517912890159).
25605001132241 is a wasteful number, since it uses less digits than its factorization.
25605001132241 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 7596040.
The product of its (nonzero) digits is 14400, while the sum is 32.
Adding to 25605001132241 its reverse (14223110050652), we get a palindrome (39828111182893).
The spelling of 25605001132241 in words is "twenty-five trillion, six hundred five billion, one million, one hundred thirty-two thousand, two hundred forty-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.087 sec. • engine limits •