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26140992747 = 3291132659037
BaseRepresentation
bin11000010110000111…
…111110010011101011
32111110210220000121120
4120112013332103223
5412014043231442
620001540110323
71613540525562
oct302607762353
974423800546
1026140992747
11100a49aa841
1250966953a3
132607a3a85c
14139db16bd9
15a2ee544ec
hex6161fe4eb

26140992747 has 16 divisors (see below), whose sum is σ = 36375639840. Its totient is φ = 16677473792.

The previous prime is 26140992739. The next prime is 26140992751. The reversal of 26140992747 is 74729904162.

It is a cyclic number.

It is not a de Polignac number, because 26140992747 - 23 = 26140992739 is a prime.

It is a Smith number, since the sum of its digits (51) coincides with the sum of the digits of its prime factors. Since it is squarefree, it is also a hoax number.

It is a self number, because there is not a number n which added to its sum of digits gives 26140992747.

It is not an unprimeable number, because it can be changed into a prime (26140992727) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1319688 + ... + 1339349.

It is an arithmetic number, because the mean of its divisors is an integer number (2273477490).

Almost surely, 226140992747 is an apocalyptic number.

26140992747 is a deficient number, since it is larger than the sum of its proper divisors (10234647093).

26140992747 is a wasteful number, since it uses less digits than its factorization.

26140992747 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2659182.

The product of its (nonzero) digits is 1524096, while the sum is 51.

The spelling of 26140992747 in words is "twenty-six billion, one hundred forty million, nine hundred ninety-two thousand, seven hundred forty-seven".

Divisors: 1 3 29 87 113 339 3277 9831 2659037 7977111 77112073 231336219 300471181 901413543 8713664249 26140992747