Base | Representation |
---|---|
bin | 111100001000010011101000… |
… | …000101100110011001010011 |
3 | 1021200100112000111000112210121 |
4 | 330020103220011212121103 |
5 | 234130302003223201121 |
6 | 2334240152123411111 |
7 | 106463100144052204 |
oct | 7410235005463123 |
9 | 1250315014015717 |
10 | 264453620131411 |
11 | 772991722aa807 |
12 | 257b0a72383a97 |
13 | b473b3c022129 |
14 | 49438a2c9d5ab |
15 | 20890a3ac7141 |
hex | f084e8166653 |
264453620131411 has 16 divisors (see below), whose sum is σ = 274092786424800. Its totient is φ = 254849396838400.
The previous prime is 264453620131403. The next prime is 264453620131457. The reversal of 264453620131411 is 114131026354462.
It is a cyclic number.
It is not a de Polignac number, because 264453620131411 - 23 = 264453620131403 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (264453620131711) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 52212801 + ... + 57053341.
It is an arithmetic number, because the mean of its divisors is an integer number (17130799151550).
Almost surely, 2264453620131411 is an apocalyptic number.
264453620131411 is a deficient number, since it is larger than the sum of its proper divisors (9639166293389).
264453620131411 is a wasteful number, since it uses less digits than its factorization.
264453620131411 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 4844150.
The product of its (nonzero) digits is 414720, while the sum is 43.
Adding to 264453620131411 its reverse (114131026354462), we get a palindrome (378584646485873).
The spelling of 264453620131411 in words is "two hundred sixty-four trillion, four hundred fifty-three billion, six hundred twenty million, one hundred thirty-one thousand, four hundred eleven".
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