Base | Representation |
---|---|
bin | 11011010100000000… |
… | …010100111001001011 |
3 | 2210200211021122101000 |
4 | 123110000110321023 |
5 | 440030111043042 |
6 | 21250020030043 |
7 | 2055512326662 |
oct | 332400247113 |
9 | 83624248330 |
10 | 29326659147 |
11 | 1148a153095 |
12 | 5825532323 |
13 | 29c4a2b166 |
14 | 15c2c4ddd9 |
15 | b6997074c |
hex | 6d4014e4b |
29326659147 has 16 divisors (see below), whose sum is σ = 44457297280. Its totient is φ = 19096428456.
The previous prime is 29326659113. The next prime is 29326659157. The reversal of 29326659147 is 74195662392.
29326659147 is a `hidden beast` number, since 2 + 9 + 3 + 2 + 6 + 6 + 591 + 47 = 666.
It is not a de Polignac number, because 29326659147 - 28 = 29326658891 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 29326659093 and 29326659102.
It is not an unprimeable number, because it can be changed into a prime (29326659157) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 12628753 + ... + 12631074.
It is an arithmetic number, because the mean of its divisors is an integer number (2778581080).
Almost surely, 229326659147 is an apocalyptic number.
29326659147 is a gapful number since it is divisible by the number (27) formed by its first and last digit.
29326659147 is a deficient number, since it is larger than the sum of its proper divisors (15130638133).
29326659147 is a wasteful number, since it uses less digits than its factorization.
29326659147 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 25259879 (or 25259873 counting only the distinct ones).
The product of its digits is 4898880, while the sum is 54.
The spelling of 29326659147 in words is "twenty-nine billion, three hundred twenty-six million, six hundred fifty-nine thousand, one hundred forty-seven".
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