Base | Representation |
---|---|
bin | 1101101100011010011010… |
… | …10100110011110111010011 |
3 | 10221121210201120010020120220 |
4 | 12312031031110303313103 |
5 | 12421334031112410303 |
6 | 144013510502204123 |
7 | 6225420653201250 |
oct | 666151524636723 |
9 | 127553646106526 |
10 | 30113313013203 |
11 | 965aa91164002 |
12 | 34641b3723643 |
13 | 13a589a1266a4 |
14 | 7616c6576427 |
15 | 3734b2b95053 |
hex | 1b634d533dd3 |
30113313013203 has 16 divisors (see below), whose sum is σ = 46664698133760. Its totient is φ = 16915953072096.
The previous prime is 30113313013177. The next prime is 30113313013207. The reversal of 30113313013203 is 30231031331103.
It is not a de Polignac number, because 30113313013203 - 25 = 30113313013171 is a prime.
It is a super-3 number, since 3×301133130132033 (a number of 41 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is not an unprimeable number, because it can be changed into a prime (30113313013207) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 12152263900 + ... + 12152266377.
It is an arithmetic number, because the mean of its divisors is an integer number (2916543633360).
Almost surely, 230113313013203 is an apocalyptic number.
30113313013203 is a deficient number, since it is larger than the sum of its proper divisors (16551385120557).
30113313013203 is a wasteful number, since it uses less digits than its factorization.
30113313013203 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 24304530346.
The product of its (nonzero) digits is 1458, while the sum is 24.
Adding to 30113313013203 its reverse (30231031331103), we get a palindrome (60344344344306).
The spelling of 30113313013203 in words is "thirty trillion, one hundred thirteen billion, three hundred thirteen million, thirteen thousand, two hundred three".
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